aufgabe 5

Gegeben §

Zugewiesener Adressbereich §

137.23.0.0/21

Anzahl Rechner §

Abteilung	Rechner
A	100
B	50
C	100
D	300
E	1000

Bearbeitung §

Adressbereich in Binär §

10001111.00010111.00000000.00000000
^^^^^^^^ ^^^^^^^^ ^^^^^

Falsche Umrechnung (erste 8 bits)

137 = 10001001

Subnetze §

A §

$$\begin{array}{c}\lceil {\log }_{2}100\rceil =7\\ ⟹\underset{\text{Netz-ID}}{\underbrace{\mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{X}}}\underset{\text{ Host-ID }}{\underbrace{0000000}}\end{array}$$

B §

$$\begin{array}{c}\lceil {\log }_{2}50\rceil =6\\ ⟹\underset{\text{Netz-ID}}{\underbrace{\mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{XX}}}\underset{\text{ Host-ID }}{\underbrace{000000}}\end{array}$$

C §

$$\begin{array}{c}\lceil {\log }_{2}100\rceil =7\\ ⟹\underset{\text{Netz-ID}}{\underbrace{\mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{X}}}\underset{\text{ Host-ID }}{\underbrace{0000000}}\end{array}$$

D §

$$\begin{array}{c}\lceil {\log }_{2}300\rceil =9\\ ⟹\underset{\text{Netz-ID}}{\underbrace{\mathrm{10001111.00010111.00000}\mathtt{XX}}}\underset{\text{ Host-ID }}{\underbrace{0.00000000}}\end{array}$$

E §

$$\begin{array}{c}\lceil {\log }_{2}1000\rceil =10\\ ⟹\underset{\text{Netz-ID}}{\underbrace{\mathrm{10001111.00010111.00000}\mathtt{X}}}\underset{\text{ Host-ID }}{\underbrace{00.00000000}}\end{array}$$

Richtig

Zusammenfassung

$$\begin{array}{rlr}A& & \mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{X}0000000\\ B& & \mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{XX}000000\\ C& & \mathrm{10001111.00010111.00000}\mathtt{XXX}.\mathtt{X}0000000\\ D& & \mathrm{10001111.00010111.00000}\mathtt{XX}0.00000000\\ E& & \mathrm{10001111.00010111.00000}\mathtt{X}00.00000000\end{array}$$

Auswahl §

$$\begin{array}{rlr}A& & \mathrm{10001111.00010111.00000}000.10000000\\ B& & \mathrm{10001111.00010111.00000}000.01000000\\ C& & \mathrm{10001111.00010111.00000}001.00000000\\ D& & \mathrm{10001111.00010111.00000}010.00000000\\ E& & \mathrm{10001111.00010111.00000}000.00000000\end{array}$$

Überlappende Präfixe

$$\begin{array}{rlr}A& & \mathrm{10001111.00010111.00000}111.10000000\\ B& & \mathrm{10001111.00010111.00000}111.00000000\\ C& & \mathrm{10001111.00010111.00000}110.00000000\\ D& & \mathrm{10001111.00010111.00000}100.00000000\\ E& & \mathrm{10001111.00010111.00000}000.00000000\end{array}$$

Antwort §

Subnetz	Netz-ID	Interface-IDs	Broadcast
A	137.32.0.128/25	137.32.0.129 - 137.32.0.254	137.32.0.255
B	137.32.0.64/26	137.32.0.65 - 137.32.0.126	137.32.0.127
C	137.32.1.0/25	137.32.1.1 - 137.32.1.126	137.32.1.127
D	137.32.2.0/23	137.32.2.1 - 137.32.3.254	137.32.3.255
E	137.32.0.0/22	137.32.0.1 - 137.32.3.254	137.32.3.255

Subnetzmasken richtig

Netzwerk-Plan §

graph TD
X((X))
A((A))
B((B))
C((C))
D((D))
E((E))
  
A---|137.32.0.128|X
B---|137.32.0.64|X
  
X---|137.32.1.0|C
X---|137.32.2.0|D
X---|137.32.0.0|E

Lösung

Abteilung	Netzwerkadresse	Host-Adressen	Router-Adresse	Broadcast- Adresse
A	137.23.6.128/25	137.23.6.130 - 137.23.6.254	137.23.6.129	137.23.6.255
B	137.23.7.0/26	137.23.7.2 - 137.23.7.62	137.23.7.1	137.23.7.63
C	137.23.6.0/25	137.23.6.2 - 137.23.6.126	137.23.6.1	137.23.6.127
D	137.23.4.0/23	137.23.4.2 - 137.23.5.254	137.23.4.1	137.23.5.255
E	137.23.0.0/22	137.23.0.2 - 137.23.3.254	137.23.0.1	137.23.3.255